Question

$10g$ of liquid at $300K$ is heated to $350K$. The liquid absorbs $6kcals$. What is the specific heat of the liquid (in $cal/g{}^{o}C$)?

• A. $6$
• B. $12$
• C. $60$
• D. $120$

Answer 1

The correct option is B $12$

From the equation of Specifc heat we know,

$C_p$ $=$ $Q$$/$($m$$\Delta T$)

Where, $C_p$ is the specific heat of the liquid

$m$ is the mass of the liquid that is $10grams$

$\Delta T$ is the change in temperature from $300K$ to $350K$ that is $50K$ or ${50}^{o}C$, because per degree change in Kelvin is the same as per degree change in Celcius scale.

$Q$ is the amount of heat absorbed, which is $6$ kcals or $6000$ cals.

Putting all the values in the equation we get,

$C_p$ $=$ $6000$$/$($10$$\ast$$50$)

This comes out to be equal to $12$ $cal$$/$$g^{o}C$

Option B is the correct answer.