Question

A liquid of mass m and specific heat c is heated to temperature 2T. Another liquid of mass m/2 specific heat 2c is heated to a temperature T. If these two liquids are nixed, the resulting temperature mixture is

• A. ( 2/3) T
• B. ( 8/5) T
• C. (3/5)T
• D. (3/ 2)T

Answer 1

The correct option is D (3/ 2)T

${\theta }_{min}=\frac{m_1{c}_1{\theta }_1+m_2{c}_2{\theta }_2}{m_1{c}_1+m_2{c}_2}$

$=\frac{m\times c\times 2T+\frac{m}{2}\left(2c\right)T}{m.c+\frac{m}{2}\left(2c\right)}$

$=\frac{3}{2}T$

Hence,

option $\left(D\right)$ is correct answer.