A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

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Solution

The correct option is D
Initial heat energy of system = Final heat energy of the system.

Temperature of mixture is given by $T = \frac{m_1c_1T_1+m_2c_2T_2}{m_1c_1+m_2c_2}

= \frac{m.c.2T+\frac{m}{2}.2.c.T}{m.c.+\frac{m}{2}.2c} = \frac{3}{2}T$

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