A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

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Solution

The correct option is D
Temperature of mixture is given by $T = \frac{m_{1} c_{1} T_{1} + m_{2} c_{2} T_{2}}{m_{1} c_{1} + m_{2} c_{2}} = \frac{m . c .2 T + \frac{m}{2} .2 . c . T}{m . c . + \frac{m}{2} .2 c} = \frac{3}{2} T$

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A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

The correct option is D Temperature of mixture is given by T=m1c1T1+m2c2T2m1c1+m2c2=m.c.2T+m2.2.c.Tm.c.+m2.2c=32T

The correct option is D
Temperature of mixture is given by $T = \frac{m_{1} c_{1} T_{1} + m_{2} c_{2} T_{2}}{m_{1} c_{1} + m_{2} c_{2}} = \frac{m . c .2 T + \frac{m}{2} .2 . c . T}{m . c . + \frac{m}{2} .2 c} = \frac{3}{2} T$