Question

10 g of liquid at 300K is heated to 350 K. The liquid absorbs 6 kcals. What is the specific heat of the liquid (in cal/g C)?

• A. 6
• B. 12
• C. 60
• D. 120

Answer 1

The correct option is B 12

q = (specific heat) X (mass) X ($\Delta T$)

$\therefore$ 6 = (specific heat) X (10 g) X (350-300)

$\therefore$ Specific Heat$=\frac{6kcal}{\left(10g\right)\times \left(50℃\right)}=\frac{6}{500}kcal/g-℃=\frac{6000}{500}cal/g-℃=12cal/g-℃$