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Question

10 grams of a sample of potassium chlorate gave on complete decomposition, 2.24 litre of oxygen at S.T.P. Calculate the mass of KCl formed and volume of O2 liberated at same time? (KClO3KCl + O2)

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Solution

2KClO32KCl+3O2 (Volume of O2 liberated =2.24 Litres)
Moles of O2 liberated =2.2422.4=0.1 mole
Moles of KCl formed =23×0.1=0.067
Mass of KCl formed =0.067×74.5=5 gm

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