Potassium chlorate on heating decomposes as under:
$2 K C l O_{3} △ - \to 2 K C l + 3 O_{2}$
Calculate (i) volume of oxygen evolved at S.T.P. (ii) weight of potassium chloride formed, when $4.9 g$ of potassium chlorate decomposes completely.
$[K = 39; O = 16; C l = 35.5]$ .

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Solution

(i) $O_{2} = 1.344 d m^{3}$
(ii) $K C l = 2.89 g$ .

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Potassium chlorate on heating decomposes as under:2KClO3△−→2KCl+3O2Calculate (i) volume of oxygen evolved at S.T.P. (ii) weight of potassium chloride formed, when 4.9 g of potassium chlorate decomposes completely.[K=39;O=16;Cl=35.5].

(i) O2=1.344 dm3(ii) KCl=2.89 g.

Potassium chlorate on heating decomposes as under:
$2 K C l O_{3} △ - \to 2 K C l + 3 O_{2}$
Calculate (i) volume of oxygen evolved at S.T.P. (ii) weight of potassium chloride formed, when $4.9 g$ of potassium chlorate decomposes completely.
$[K = 39; O = 16; C l = 35.5]$ .

(i) $O_{2} = 1.344 d m^{3}$
(ii) $K C l = 2.89 g$ .