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Question

10 mL of a 1 M solution of sodium hydroxide is pipetted into a 100 mL standard flask and made upto the mark. 10 mL of this solution requires 20 mL of HCl for complete neutralization. Calculate the molarity of HCl solution.

A
0.05 M
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B
0.01 M
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C
0.001 M
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D
0.005 M
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Solution

The correct option is A 0.05 M
Molarity of the original NaOH solution V1= 1 M
Volume of the original NaOH solution M1 = 10 mL
Volume of the diluted NaOH solution V2= 100 mL
Molarity of the diluted NaOH solution M2 = V1M1V2=10×1100=0.1 M

The chemical reaction involved in the titration is,
NaOH+HClNaCl+H2O
Given,
Volume of the HCl solution required for the titration V3 = 20 mL
Let, the molarity of HCl solution be = M3
Thus, M2V2=M3V3
Molarity of the HCl solution M3 = V2M2V3
Molarity of HCl M3 = 10×0.120=0.05 M

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