$10$ mL of a gaseous hydrocarbon is exploded with $100$ mL of oxygen. The residual gas on cooling is found to measure $95$ mL of which $20$ mL is absorbed by caustic soda and the remainder by alkaline pyrogallol. The formula of the hydrocarbon is :

C H_{4}

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C_{2} H_{6}

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C_{2} H_{4}

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C_{2} H_{2}

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Solution

The correct option is B $C_{2} H_{2}$
$C_{x} H_{y} 1 m L 10 m L + (x + \frac{y}{4}) O_{2} (x + \frac{y}{4}) m L 10 ⎛ ⎜ ⎝ x + \frac{y}{4} ⎞ ⎟ ⎠ m L \to x C O_{2} x m L 10 x m L + + \frac{y}{2} H_{2} O \frac{y}{2} -$
Volume absorbed by $K O H =$ Volume of $C O_{2}$
$∴$ Volume of $C O_{2} = 20$ mL
$∴ 10 x = 20$
$x = 2$ mL $= 2$ mol.
Volume absorbed by alkaline pyrogallol $=$ volume of $O_{2}$ $= 95 - 20$ $= 75$ mL.
Excess of $O_{2} = 75$ mL
Total $O_{2} = 100$ mL
Volume of $O_{2}$ reacted $= 100 - 75 = 25$ mL
$∴ 10 (x + \frac{y}{4}) = 25$ mL
$∴ y = 2$
Formula of hydrocarbon $= C_{2} H_{2}$

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10 mL of a gaseous hydrocarbon is exploded with 100 mL of oxygen. The residual gas on cooling is found to measure 95 mL of which 20 mL is absorbed by caustic soda and the remainder by alkaline pyrogallol. The formula of the hydrocarbon is :

$10$ mL of a gaseous hydrocarbon is exploded with $100$ mL of oxygen. The residual gas on cooling is found to measure $95$ mL of which $20$ mL is absorbed by caustic soda and the remainder by alkaline pyrogallol. The formula of the hydrocarbon is :