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Gay Lussac's Law, Avagadro's Law

10 ml of a mi...

Question

10 ml of a mixture of $C H_{4}, C_{2} H_{4}$ and $C O_{2}$ were exploded with excess of air. After explosion, there was contraction on cooling of 17 ml and after treatment with KOH, there was further reduction of 14 ml. What is the composition of the mixture?

A

C H_{4} = 4.5 m l, C O_{2} = 1.5 m l

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B

C H_{4} = 3.6 m l, C O_{2} = 2.5 m l

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C

C H_{4} = 4.8 m l, C O_{2} = 1.8 m l

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D

C H_{4} = 5.1 m l, C O_{2} = 2.8 m l

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Solution

The correct option is D $C H_{4} = 4.5 m l, C O_{2} = 1.5 m l$
The contraction on cooling is due to the condensation of water vapour. Thus 17 ml of water are formed in the reaction.
The contraction in the volume of 14 ml is due to the dissolution of carbon dioxide gas. Hence, 14 g of carbon dioxide is present in the mixture after the explosion.
$C H_{4} 4.5 m l \to C O_{2} 4.5 m l + 2 H_{2} O 9 m l$
$C_{2} H_{4} 4 m l \to 2 C O_{2} 8 + 2 H_{2} O 8 m l$

Hence, the composition of the mixture is 4.5 ml methane and 1.5 ml of carbon dioxide.

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