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Gay Lussac's Law, Avagadro's Law

10 ml mixture...

Question

10 ml mixture of $C O, C H_{4}$ and $N_{2}$ , exploded with an excess of oxygen, gave a contraction of 6.5 ml. There was a further contraction of 7ml when the residual gas was treated with $K O H$ . Volume of $C O, C H_{4}$ and $N_{2}$ respectively, is :

5ml, 2ml, 3ml

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2ml, 6ml, 4ml

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1ml, 8ml, 9ml

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4ml, 3ml, 5ml

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Solution

The correct option is A 5ml, 2ml, 3ml
$Solution :$
Let the volumes of $C O, C H_{4}$ , and $N_{2}$ in the mixture be x ml, y ml, and (10-x-y) ml respectively. We ignore the volume of water formed in the combustion as it is a liquid and its volume is small. Nitrogen combusts only at very very high temperatures. So it remains unreactive.

$2 C O + O_{2} ⟹ 2 C O_{2}$ $C H_{4} + 2 O_{2} ⟹ C O_{2} + 2 H_{2} O$
x ml x/2 ml x ml y ml 2 y ml y ml (liquid)

The volume of oxygen used: $2 y + \frac{x}{2} m l$
Total volume of all gases before combustion $= 10 + 2 y + \frac{x}{2} m l$
After combustion the total volume is: 10 ml
as $C O_{2} : x + y$ $N_{2} : 10 - x - y$

Reduction in volume: $10 + 2 y + \frac{x}{2} - 10 = 2 y + \frac{x}{2} = 6.5 m l$
$⟹ 4 y + x = 13 m l$ --- (1)

When the mixture of $C O_{2} + N_{2}$ passes over KOH, all of $C O_{2}$ is absorbed. Only $N_{2}$ remains. Then the reduction of 7 ml corresponds to that of $C O_{2}$ .
$⟹ x + y = 7 m l$ --- (2)

Solving the two equations, x = 5 ml and y = 2 ml

Volumes of $C_{O} = 5 m l$ , $C H_{4} = 2 m l$ , $N_{2} = 3 m l$ .

$Hence A is the correct option$

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C O

C H_{4}

and

N_{2}

gas has total volume of 40

m L

. This mixture is exploded with excess of oxygen, on cooling 30

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m L

is observed. Find the composition of the mixture in

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C H_{4}

and

N_{2}

gas has total volume of 40

m L

. This mixture is exploded with excess of oxygen, on cooling 30

m L

of contraction is observed and when this mixture is treated with aqueous

K O H

a further contraction of 30

m L

is observed. Find the composition of the mixture in

m L

Q. A mixture of

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and

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was burnt in excess of

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solution to show a contraction of

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10 ml mixture of CO,CH4 and N2, exploded with an excess of oxygen, gave a contraction of 6.5 ml. There was a further contraction of 7ml when the residual gas was treated with KOH. Volume of CO,CH4 and N2 respectively, is :

10 ml mixture of $C O, C H_{4}$ and $N_{2}$ , exploded with an excess of oxygen, gave a contraction of 6.5 ml. There was a further contraction of 7ml when the residual gas was treated with $K O H$ . Volume of $C O, C H_{4}$ and $N_{2}$ respectively, is :