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Introduction to Alcohols

10 ml of hydr...

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10 ml of hydrocarbon was completely burnt in 80 ml of O2 at ntp.The remaining gaseous mixture occupies 70 ml at Ntp.The volume becomes 50 ml when passed through KOH,what is the formula of hydrocarbon?

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10

mL of a gaseous hydrocarbon was burnt completely in

80

O_{2}

at NTP. The remaining gas occupied

70

mL at NTP. This volume became

50

mL on treatment with KOH solution. What is the formula of the hydrocarbon?

Q. Ten milliliters of a gaseous hydrocarbon was burnt completely in 80 ml of

O_{2}

at STP. The Volume of the remaining gas is 70 ml. The volume became 50 ml on treatment with NaOH. The formula of the hydrocarbon is :

15 mL

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357.15 mL

21 %

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Q. 10 ml of hydrocarbon burnt with 80 ml of

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Q. 7.5 ml of a gaseous hydrocarbon was exploded with 36 ml of

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. On cooling, the volume of gases was found to be 28.5 ml, 15 ml of which was absorbed by

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and the rest was absorbed in a solution of alkaline pyrogallol. The formula of hydrocarbon is:

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