Question

$10$ moles of an ideal gas confined to a volume of $10\text{L}$ is released into atmosphere at $300\text{K}$ where the pressure is $1\text{bar}$. The work done by the gas is:
$(R=0.083{\text{L bar K}}^{-1}{\text{mol}}^{-1})$

• A. $249\text{L bar}$
• B. $259\text{L bar}$
• C. $-239\text{L bar}$
• D. $-220\text{L bar}$

Answer 1

The correct option is C $-239\text{L bar}$

Initial volume, $V_1=10\text{L}$
$V_2\left(final\right)=\frac{nRT}{P}=\frac{10\times 0.083\times 300}{1}=249$
$W=-P\Delta V=-1\times (249-10)=-239\text{L bar}$