Question

$10\text{g}$ of hydrogen and $64\text{g}$ of oxygen were filled in a steel vessel and exploded. What will be the amount of water produced in this reaction?

• A. $1\text{mol}$
• B. $2\text{mol}$
• C. $3\text{mol}$
• D. $4\text{mol}$

Answer 1

The correct option is D $4\text{mol}$

Moles of hydrogen $=\frac{10}{2}=5\text{mol}$
Moles of oxygen $=\frac{64}{32}=2\text{mol}$
$2H_2+O_2\to 2H_{2}O$
Thus, $O_2$ is the limiting reactant.
$\therefore$ amount of water produced $=2\times 2\text{mol}$
$=4\text{mol}$