wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

10 mL of M200 H2SO4 is mixed with 40mL of M200 H2SO4. The pH of resulting solution is:

A
2.301
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.301
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 2
Applying
M1V1+M2V2=M3V3(1200×101000)+(1200×401000)=M3×501000M3=1200
Now H2SO42H++SO23
Since 2H+ are there so concentration
=2×M3=2200=1100pH=log10(1100) =[log10(1)log10(100)]pH=[02]=2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon