Question

${10}^{th}$ term of the A.P . 1, 4, 7 , 10 .....

Answer 1

Given$,$ $a=1$ $D=3$ $,$ $n=10$

$a_n=a+\left(n-1\right)d$

$a_{10}=1+\left(10-1\right)3$

$a_{10}=1+9\times 3$

$a_{10}=1+27$

$a_{10}=28$