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Question 10
If 17th term of an A.P exceeds its 10th term by 7. Find the common difference.


Solution

We know that,for an A.P., an=a+(n1)da17=a+(171)da17=a+16dSimilarly, a10=a+9dIt is given that,a17a10=7(a+16d)(a+9d)=77d=7d=1
Therefore, the common difference is 1.

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