Question

# The $$17^{th}$$ term of an $$AP$$ exceeds its $$10^{th}$$ term by $$7$$. Find the common difference.

Solution

## We know that,For an A.P $$n^{th}$$ term is given as $$a_{n}=a+(n-1)d$$$$a_{17}=a+(17-1)d$$$$a_{17}=a+16d$$Similarly, $$a_{10}=a+9d$$It is given that$$a_{17}-a_{10}=7$$$$(a+16d)-(a+9d)=7$$$$7d=7$$$$\therefore d=1$$Therefore, the common difference is $$1$$.MathematicsRS AgarwalStandard X

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