10. The number of all possible matrices of order 3 x 3 with each entry 0 or 1 is:(A) 27(B) 18(C) 81(D) 512

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Solution

The correct option is (D).

The matrix of order 3×3 has a total of 9 elements and each of these elements can be either 0 or 1 .

Therefore, using the multiplication principle, the number of all possible matricesis,

2 9 =512

Thus, the correct answer is 512.

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Similar questions

The number of all possible matrices of order 3 × 3 with each entry 0 or 1 is:

(A) 27

(B) 18

(D) 512

The number of all possible matrices of order $3 \times 3$ with each entry 0 to 1 is
(a)27
(b)18
(c)81
(d)512

3 \times 3

0

1

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