Question

The number of all possible matrices of order 3 × 3 with each entry 0 or 1 is
(a) 27
(b) 18
(c) 81
(d) 512

Answer 1

(d) 512

There are 9 elements in a 3$\times$3 matrix and one element can be filled in two ways, either with 0 or 1.

Thus,
Total possible matrices = $2^9$ = 512