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Concentration Terms

100 g of Ca...

Question

100 g of $C a C O_{2}$ is treated with 500 ml M/2 solution of HCL, find out the volume of CO2 evolved at S.T.P. Which substance is limiting reagent?
$C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}$

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Solution

$M a s s o f C a C O_{3} = 100 g M o l a r M a s s o f C a C O_{3} = 100 g / m o l V o l u m e o f 0.5 M s o l u t i o n o f H C l = 500 m l = 0.5 l i t r e M o l e o f C a C O_{3} = \frac{100}{100} = 1 m o l e U s i n g l a w o f e q u i v a l e n c e, n u m b e r o f m o l e s o f H C l = M o l a r i t y \times V o l u m e = 0.5 \times 0.5 = 0.25 m o l e C a C O_{3} + 2 H C l ⟶ C a C l_{2} + H_{2} O + C O_{2} 2 m o l e s o f H C l = 1 m o l e o f C O_{2} 0.25 m o l e o f H C l = 0.125 m o l e o f C O_{2} 1 m o l e a t S . T . P = 22.7 l i t r e v o l u m e ⟹ 0.125 m o l e a t S . T . P = 22.7 \times 0.125 l i t r e v o l u m e V o l u m e o c c u p i e d b y C O_{2} = 2.84 l i t r e a t S . T . P \to H C l i s a l i m i t i n g r e a g e n t .$

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C a C O_{3}

C O_{2}

C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

C a C O_{3} = 100 u, H C l = 36.5 u C O_{2} = 44 u)

H C l

C a C O_{3}

H C l

C a C O_{3} + 2 H C l \to C a C l_{2} + C O_{2} + H_{2} O

C a C O_{3} + 2 H C l ⟶ C a C l_{2} + H_{2} O + C O_{2}

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50 %

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C a C O_{3} (s)

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C a C O_{3} + 2 H C l \to C O_{2} + H_{2} O + C a C l_{2}

C a C O_{3} = 100

C O_{2} = 44

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C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

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