You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Chemistry

Salt of Strong Acid and Strong Bases

100 mL of 0.1...

Question

$100 m L$ of $0.1 M H C l$ is titrated against the $0.1 M N a O H$ solution. What will be the $p H$ of the solution when $100 m L N a O H$ is added ?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 7
mmol of $H C l = 100 \times 0.1 = 10$
mmol of $N a O H added = 100 \times 0.1 = 10$

$H C l (a q) + N a O H (a q) \to N a C l (a q) + H_{2} O (l) I n i t i a l : 101000 F i n a l : 001010$

After titration , no acid or base is remaining as both will completely neutralizes each other and salt $N a C l$ is formed which does not hydrolyzed infact it rather hydrated in water.

So , the resultant solution will be neutral and the pH of the solution will be equal to 7.

Suggest Corrections

Similar questions

100 m L

0.1 M H C l

is titrated against the

0.1 M N a O H

solution. What will be the

p H

of the solution when

100 m L N a O H

is added ?

Q. A solution of weak acid

H A

was titrated with base

N a O H

. The equivalence point was reached when

36.12 m L

0.1 M N a O H

was added. Now

18.06 m L

0.1 M H C l

were added to titrated solution, the pH was found to be

4.92

. What will be the

p H

of the solution obtained by mixing

10 m L

0.2 M N a O H

and

10 m L

0.2 M H A

20 m L

1 M H C l

is titrated against the

1 M N a O H

solution. Calculate the

p H

of the solution when

30 m L N a O H

is added?

Q. A solution of weak acid was titrated with base

N a O H

. The equivalence point was reached when

36.12 m L

0.1 M N a O H

have been added. Now

18.06 m L 0.1 M H C l

were added to titrated solution, the

p H

was found to be

4.92

. What is

K_{a}

of acid?

100 m L

of a

0.1 M C H_{3} C O O N a (a q)

is titrated against a

0.1 M H C l (a q)

. Calculate the

p H

of the solution when

50 m L

H C l

was added.
Given:

p K_{a} (C H_{3} C O O H) = 4.74 a t 25^{o} C

Join BYJU'S Learning Program

Explore more

Salt of Strong Acid and Strong Bases

Standard XIII Chemistry

Join BYJU'S Learning Program

100 mL of 0.1 M HCl is titrated against the 0.1 M NaOH solution. What will be the pH of the solution when 100 mL NaOH is added ?

$100 m L$ of $0.1 M H C l$ is titrated against the $0.1 M N a O H$ solution. What will be the $p H$ of the solution when $100 m L N a O H$ is added ?