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Standard X
Chemistry
Ionisation Energy
100 mL of 0.1...
Question
100 mL of 0.1N hypo decolourised iodine by the addition of x g of crystalline copper sulphate to excess of KI. The value of 'x' is(mol. weight of CuSO4.5H2O is 250)-1)5.0g, 2)1.25g, 3)2.5g, 4)4g.
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Q.
100
m
L
of
0.1
n
hypo decolourised iodine by the addition of
x
g
of crystalline copper sulphate to excess of
K
l
.The value of
x
is:
Q.
1.2475
g of crystalline copper sulphate was dissolved in water and excess of KI was added. The liberated iodine consumed
50
mL
N
10
N
a
2
S
2
O
3
solution to reach the end point of the titration.The number of water molecules of hydration in crystalline copper sulphate salt is
:
Q.
2.5
g sample of copper is dissolved in excess of
H
2
S
O
4
to prepare
100
ml of
0.02
M
C
u
S
O
4
(
a
q
)
.
10
ml of
0.02
M
solution of
C
u
S
O
4
(
a
q
)
is mixed with excess of
K
I
to show the following changes:
C
u
S
O
4
+
2
K
I
⟶
K
2
S
O
4
+
C
u
I
2
2
C
u
I
2
⟶
C
u
2
I
2
+
I
2
The liberated iodine is titrated with hypo (
N
a
2
S
2
O
3
) which requires
V
ml of
0.1
M
hypo solution for its complete reduction.
The color of the solution developed during the addition of
K
I
to
C
u
S
O
4
solution is :
Q.
2.5
g sample of copper is dissolved in excess of
H
2
S
O
4
to prepare
100
ml of
0.02
M
C
u
S
O
4
(
a
q
)
.
10
ml of
0.02
M
solution of
C
u
S
O
4
(
a
q
)
is mixed with excess of
K
I
to show the following changes:
C
u
S
O
4
+
2
K
I
⟶
K
2
S
O
4
+
C
u
I
2
2
C
u
I
2
⟶
C
u
2
I
2
+
I
2
The liberated iodine is titrated with hypo (
N
a
2
S
2
O
3
) which requires
V
ml of
0.1
M
hypo solution for its complete reduction.
The amount of
I
2
liberated in the reaction of
10
ml of
0.02
M
solution with excess
K
I
is
:
Q.
2.5
g sample of copper is dissolved in excess of
H
2
S
O
4
to prepare
100
ml of
0.02
M
C
u
S
O
4
(
a
q
)
.
10
ml of
0.02
M
solution of
C
u
S
O
4
(
a
q
)
is mixed with excess of
K
I
to show the following changes:
C
u
S
O
4
+
2
K
I
⟶
K
2
S
O
4
+
C
u
I
2
2
C
u
I
2
⟶
C
u
2
I
2
+
I
2
The liberated iodine is titrated with hypo (
N
a
2
S
2
O
3
) which requires
V
ml of
0.1
M
hypo solution for its complete reduction.
The volume (
V
) of hypo required is:
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