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Concentration Terms

100 mL of 0...

Question

$100 m L$ of $0.2 N H C l$ solution is added to $100 m L$ of $0.2 N A g N O_{3}$ solution. The molarity of nitrate ions in the resulting mixture will be:

0.05 M

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0.5 M

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0.1 M

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0.2 M

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Solution

The correct option is B $0.1 M$
Millimoles of $N O_{3}^{-} = 100 \times 0.2 = 20$
Total volume of the mixture $= 100 + 100 = 200 m l$
Molarity of nitrate ion in the mixture $= \frac{20}{200} = 0.1 M$

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