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Question
100 ml of 0.5 N NaOH solution is added to 10 ml of 3 N H2SO4 solution and 20 ml of 1 N HCl solution. The mixture is :
100 ml of 0.5 N NaOH solution is added to 10 ml of 3 N H2SO4 solution and 20 ml of 1 N HCl solution. The mixture is :
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Solution
The correct option is B neutral
No of mili Equivalents = Molarity × n-factor × volume(mili liters)Or No of mili equivalents is also = normality × volume ( mili liters)
No of equivalents of Base added = 0.5 × 100 = 50No of equivalents of acid = 3 × 10 + 1 × 20 = 50 ( since two acids are added so we have to calculate total equivalents of both acids )
Since milliequivalents of acid and base are equal hence the solution is neutral.Option C is correct.
No of mili Equivalents = Molarity × n-factor × volume(mili liters)
Or No of mili equivalents is also = normality × volume ( mili liters)
No of equivalents of Base added = 0.5 × 100 = 50
No of equivalents of acid = 3 × 10 + 1 × 20 = 50 ( since two acids are added so we have to calculate total equivalents of both acids )
Since milliequivalents of acid and base are equal hence the solution is neutral.
Option C is correct.
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