Question

$100$ mL of $0.5$N $NaOH$ were added to $20$ml of $1$N $HCl$ and $10$mL of $3$N $H_{2}S{O}_4$. The solution is:

• A. acidic
• B. basic
• C. neutral
• D. none of these

Answer 1

Answer: (C)

neutral

$\left[O{H}^{-}\right]$ moles $=100\times 0.5=50$ $mmol$

Normality only gives $3$

Moles of $\left[H^{+}\right]=20\times 1+10\times 3=50$ $mmol$

$\left[H^{+}\right]=\left[O{H}^{-}\right]$

Solution is neutral.