5 ml of N HCl, 20 ml of $N / 2 H_{2} S O_{4}$ and 30 ml of $N / 3 H N O_{3}$ are mixed together and volume made to one litre. The normality of the resulting solution is

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100 ml of each of 0.5 N NaOH, N/5 HCl and N/10 H2SO4 are mixed together. The resulting solution will be :

The correct option is C AlkalineEquivalents of Acid =normality×volume=(15+110)×0.1=0.03Equivalents of base =0.5×0.1=0.05As the equivalents of base are more than the equivalents of acid, the resulting solution will be alkaline.

100 ml of each of 0.5 N $N a O H$ , N/5 $H C l$ and N/10 $H_{2} S O_{4}$ are mixed together. The resulting solution will be :

The correct option is C Alkaline
Equivalents of Acid $= n o r m a l i t y \times v o l u m e = (\frac{1}{5} + \frac{1}{10}) \times 0.1 = 0.03$

Equivalents of base $= 0.5 \times 0.1 = 0.05$

As the equivalents of base are more than the equivalents of acid, the resulting solution will be alkaline.