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Limiting Reagent or Reactant

100 ml of gas...

Question

100 ml of gaseous mixture has 20ml of ethylene and remaining are oxygen. The mixture is fired and coated to room temperature determine the final composition of gaseous mixture.

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Solution

$H - C \equiv C - H + \frac{5}{2} O_{2} ⇌ 2 {C O}_{2} H_{2} O 20 m l 100 m l ↓ l i m i t i n g r e a g e n t 100 - \frac{5}{2} \times 2040 m l {C O}_{2} = 50 m l o f O_{2}$

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