100 mL of H2O2 is oxidised by 100 mL of 0.01MKMnO4 in acidic medium (MnO⊝4 reduced to Mn2+). 100 mL of the same H2O2 is oxidised by V mL of 0.01MKMnO4 in basic medium (MnO⊝4 reduced to MnO2). Hence, V is :
A
500
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B
100
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C
1003
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D
5003
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Solution
The correct option is D5003 As given, 100×5N(MnO⊝4)≡V×3N(MnO⊝4) V=5003mL