CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Stoichiometric Calculations

100 mL of H...

Question

$100$ mL of $H_{2} O_{2}$ is oxidised by $100$ mL of $0.01 M$ $K M n O_{4}$ in acidic medium ( $M n O_{4}^{⊝}$ reduced to $M n^{2 +}$ ). $100$ mL of the same $H_{2} O_{2}$ is oxidised by $V$ mL of $0.01 M$ $K M n O_{4}$ in basic medium ( $M n O_{4}^{⊝}$ reduced to $M n O_{2}$ ). Hence, $V$ is :

A

500

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

\frac{100}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

\frac{500}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{500}{3}$
As given,
$100 \times 5 N (M n O_{4}^{⊝}) \equiv V \times 3 N (M n O_{4}^{⊝})$
$V = \frac{500}{3} m L$

Suggest Corrections

thumbs-up

0

Similar questions

100

0.01 M

K M n O_{4}

100

H_{2} O_{2}

in acidic medium. The volume of same

K M n O_{4}

required in strong alkaline medium to oxidise

100

H_{2} O_{2}

100

1 M K M n O_{4}

100

H_{2} O_{2}

in acidic medium (when

{M n O_{4}}^{-}

M n^{2 +}

). Volume of same

K M n O_{4}

required to oxidise

100

H_{2} O_{2}

in neutral medium (when

{M n O_{4}}^{-}

M n O_{2}

100

0.01 M

K M n O_{4}

100

H_{2} O_{2}

in acidic medium. The volume of the same

K M n O_{4}

required in alkaline medium to oxidize

100

H_{2} O_{2}

M n O_{4}^{⊝}

M n^{2 +}

in acidic medium and to

M n O_{2}

in alkaline medium)

Q. In acidic medium, 100 ml of 1 M

K M n O_{4}

solution oxidizes 100 ml of

H_{2} O_{2}

solution. The volume of 0.01 M

K M n O_{4}

, required to oxidize the same volume of

H_{2} O_{2}

in alkaline medium in ml is :

H_{2} C_{2} O_{4}

required to reduce 100 ml of 0.008M

K M n O_{4}

IN acidic medium is x g and to neutralize 100 ml of 0.01M

M g {(O H)}_{2}

IS y g, then the relation between x and y is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Stoichiometric Calculations

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Stoichiometric Calculations

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon