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Byju's Answer
Standard XII
Chemistry
Molarity
100 ml of K...
Question
100
ml of
K
M
n
O
4
solution is exactly reduced by
100
ml of
0.5
M oxalic acid under acidic condition. The molarity of
K
M
n
O
4
solution is:
A
0.1
M
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B
0.2
M
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C
0.05
M
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D
0.5
M
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Solution
The correct option is
B
0.2
M
2
K
M
n
O
4
+
5
H
2
C
2
O
4
+
6
H
+
→
2
M
n
2
+
+
10
C
O
2
+
8
H
2
O
5
×
M
K
M
n
O
4
×
V
K
M
n
O
4
=
2
×
M
H
2
C
2
O
4
×
V
H
2
C
2
O
4
5
×
M
K
M
n
O
4
×
100 mL
=
2
×
0.5 M
×
100 mL
M
K
M
n
O
4
=
0.2
M.
The molarity of
K
M
n
O
4
solution is
0.2
M.
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0
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