wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

100 ml of KMnO4 solution is exactly reduced by 100 ml of 0.5 M oxalic acid under acidic condition. The molarity of KMnO4 solution is:

A
0.1 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.2 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.05 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.5 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.2 M
2KMnO4+5H2C2O4+6H+2Mn2++10CO2+8H2O

5×MKMnO4×VKMnO4=2×MH2C2O4×VH2C2O4

5×MKMnO4× 100 mL =2× 0.5 M × 100 mL

MKMnO4=0.2 M.

The molarity of KMnO4 solution is 0.2 M.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon