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Question
100 mL of PH3 on decomposition produced phosphorus and hydrogen. The change in volume is:
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Solution
The correct option is D none of the above
The equation for the decomposition is:4PH3(g)=P4(s)+6H2(g) (Elemental phosphorus exists as tetra atomic molecules).
When the temperature and pressure remain the same, 4 ml of PH3 will give 6 ml of H2. (On applying Gay-Lussac's law ).
Hence, 100 ml of PH3 will yield 150 ml of H2.
Increase in volume = (150-100) ml = 50 ml. (The volume of solid phosphorus is negligible).
The equation for the decomposition is:
4PH3(g)=P4(s)+6H2(g) (Elemental phosphorus exists as tetra atomic molecules).
When the temperature and pressure remain the same, 4 ml of PH3 will give 6 ml of H2. (On applying Gay-Lussac's law ).
Hence, 100 ml of PH3 will yield 150 ml of H2.
Increase in volume = (150-100) ml = 50 ml. (The volume of solid phosphorus is negligible).
When the temperature and pressure remain the same, 4 ml of PH3 will give 6 ml of H2. (On applying Gay-Lussac's law ).
Hence, 100 ml of PH3 will yield 150 ml of H2.
Increase in volume = (150-100) ml = 50 ml. (The volume of solid phosphorus is negligible).
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