$100 mL$ of $0.6 M$ acetic acid is shaken with $2 g$ activated carbon. The final concentration of the solution after adsorption is $0.5 M .$ What is the amount of acetic acid in gram adsorbed per gram of carbon

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Solution

Before adsorption concentration $= 0.6 M$
After adsorption concentration $= 0.5 M$
Volume of the solution $= 100 mL$
$∴$ milliequivalent of acetic acid adsorbed
$= 100 \times 0.1 = 10$
$= 10 \times 60 \times 10^{- 3} g = 0.6 g$ acetic acid
$∴ 2 g$ activated carbon has adsorbed $0.6 g$ acetic acid $1 g$ will adsorb $0.3 g$

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100 mL of 0.6 Macetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid in gram adsorbed per gram of carbon

Before adsorption concentration =0.6 M After adsorption concentration =0.5 M Volume of the solution =100 mL ∴ milliequivalent of acetic acid adsorbed =100×0.1=10 =10×60×10−3 g=0.6 g acetic acid ∴ 2 g activated carbon has adsorbed 0.6 g acetic acid 1 g will adsorb 0.3 g

$100 mL$ of $0.6 M$ acetic acid is shaken with $2 g$ activated carbon. The final concentration of the solution after adsorption is $0.5 M .$ What is the amount of acetic acid in gram adsorbed per gram of carbon