1000 g of sucrose solution in water is cooled to -3.534 C. What mass of ice would be separated out at this temperature? K freezing water =1.86 K mol g

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1000 gm of 1 (m) sucrose solution in water is cooled to - 3.554-degree centigrade. What mass of ice would be separated out in nearest possible integers in gm at this temperature?

For water $K_{f}$ = 1.86 $K m o l^{- 1} k g$

Q. 100 g of sucrose solution in water is cooled to

- {0.5}^{o} C

. What is the mass(g) of ice in decagram (nearest integer) that would be separated out at this temperature, if solution to freeze at

- {0.38}^{o} C

? (

K_{f}

for

H_{2} 6 = 1.86 K m o l^{- 1} k g)

1000 g

1 m

aqueous solution of sucrose is cooled and maintained at

- {3.534}^{\circ} C .

What amount of ice will separate out at this temperature?

K_{f} (H_{2} O) = 1.86 K \cdot k g \cdot m o l^{- 1} .

Q. A solution of

1

moles of sucrose in

1000

grams of water freezes at

- {0.2}^{\circ} C

. How many grams of ice would have separated at

- {0.4}^{\circ} C

Q. A solution of sucrose (molar mass

= 342 g . {m o l}^{- 1}

) has been prepared by dissolving

68.5 g

of sucrose in

1000 g

of water. The freezing point of solution obtained will be:
(

K_{f}

for water

= 1.86 K k g {m o l}^{- 1}

)

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