Question

$1000kHz$ carrier wave is amplitude modulated by the signal frequency$200Hz-4000Hz$. The channel width of this case is

• A. $8kHz$
• B. $7.6kHz$
• C. $3.8kHz$
• D. $400kHz$
• E. $4kHz$

Answer 1

The correct option is A

$8kHz$

Step 1: Given data:

Frequency range $=200Hz-4000Hz$

Frequency of modulating signal, $f=4000Hz$

Step 2: Calculate the channel width:

Channel width $=2\times f$

$=2\times 4000Hz$

$=8000\mathbf{}\left[\because {10}^{3}Hz=1KHz\right]$

$=8\times {10}^3$

$=8kHz$

Hence, option (A) is correct answer.