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Question
100g of CaCO3 reacts with 1 litre 1N HCl. On completion of reaction, the mass of CO2 liberated is :
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Solution
The correct option is C 22g
100g of CaCO3 would be 1 mol because the molecular weight is 100.089. 1 L of 1M HCL would also be 1 mol of HCl, so in the reaction we can write CaCO3 + 2HCl --> CO2 + H2O+CaCl2
so 1/2mol of CO2 would come out of the reaction, which would be 22.005 grams because tahts the molecular weigt of CO2
Hence 22g is the answer.
100g of CaCO3 would be 1 mol because the molecular weight is 100.089. 1 L of 1M HCL would also be 1 mol of HCl, so in the reaction we can write CaCO3 + 2HCl --> CO2 + H2O+CaCl2
so 1/2mol of CO2 would come out of the reaction, which would be 22.005 grams because tahts the molecular weigt of CO2
Hence 22g is the answer.
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