Question

$100g$ of ice at $0^{o}C$ is mixed with $100g$ of water at ${100}^{o}C$. What will be the final temperature of the mixture?

• A. ${10}^{o}C$
• B. ${20}^{o}C$
• C. ${30}^{o}C$
• D. $0^{o}C$

Answer 1

The correct option is A ${10}^{o}C$

Amount of heat absorbed in melting $=$ lateral heat $\times$ mass $=80\times 100$ cal

Amount of heat absorbed $=$ mass $\times$ specific heat $\times$ kmp $=8000$ cal

$=(100.k\times x)$ (specific heat of water $=1$ cal/g)

$=100x$ cal

Total heat absorbed $=(8000+100x)$ cal

By the condition of the equilibrium,

$(8000+100x)=(10000-100x)\Rightarrow 200x=2000\Rightarrow x=10$

Ans :- ${10}^{0}C$