Question

100ml of a solution contains $6.02\times {10}^{22}$ molecules of oxalic acid. Its normality is:

• A. $1N$
• B. $2N$
• C. $3N$
• D. $4N$

Answer 1

The correct option is B $2N$

Total moles $=\frac{6.02\times {10}^{22}}{6.02\times {10}^{23}}$

$=\frac{1}{10}$ mole

Molarity $=\frac{Numberofmoles}{V\left(ml\right)}\times 1000$

$=\frac{1}{10}\times \frac{1000}{100}=1$

Normality $=$ molarity $\times$ acidic Hydrogen

$=1\times 2$

$=2N$