119.An ac voltage is applied to a resistance R and an inductor L in series. If R and inductive reactance are both equal to 3 ohm, the phase difference between the applied voltage and the current in the circuit is 1) pie/6 2) pie/4 3) pie/2 4) 0

Open in App

Solution

Suggest Corrections

Similar questions

3 Ω

When an a.c. voltage is applied across series combination of a resistance R and an inductor of

inductance 2 milli Henry, the phase difference between current and applied voltage is $\frac{π}{6}$ radian.

When same a.c. voltage is applied across series combination of same resistance and a condenser of

capacity , $5 μ F$ the phase difference between current and applied voltage is $\frac{π}{3}$ radian. The value of

R is

A C

R

L

45^{o}

A C

V = V_{0} sin 100 t

π / 4

A C

E = E_{0} sin 100 t

\frac{π}{4}

Join BYJU'S Learning Program