Question

12 g $N_2$, 4 gm $H_2$ and 9 gm $O_2$ are put into a one litre container at ${27}^{\circ }C$. What is the total pressure?

• A. 33.37 atm
• B. 66.74 atm
• C. 133.48 atm
• D. None of these

Answer 1

Answer: (B)

66.74 atm

12 gm $N_2$ corresponds to $\frac{12}{28}=0.429mol$.

4 gm $H_2$ corresponds to $\frac{4}{2}=2mol$

9 gm $O_2$ corresponds to $\frac{9}{32}=0.28$.

The total number of moles are $0.429mol+2mol+0.28mol=2.71mol$

The total pressure is $\frac{nRT}{V}=\frac{2.71\times 0.0821\times 300}{1}=66.74atm$.

Hence, the correct answer is option $\text{B}$.