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Standard XII

Chemistry

Dalton's Law of Partial Pressures

A gaseous mix...

Question

A gaseous mixture contain 1 gm of $H_{2},$ 4 gm of $H e$ 7gm of $N_{2}$ and 8gm of $O_{2}$ . The gas having the highest partial pressure is:

H_{2}

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O_{2}

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H e

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N_{2}

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Solution

The correct option is C $H e$
Given,
1gm of hydrogen, 4gm of helium,7gm of nitrogen,8gm of oxygen
Now,
Given mole of hydrogen $\frac{1}{2}$ mole
mole of helium $= \frac{4}{4}$ =1mole
mole of nitrogen $= \frac{7}{28} = \frac{1}{4}$ mole
mole of oxygen $= \frac{8}{32} = \frac{1}{4}$ mole
We know according to ideal gas equation
$P \propto n$ , P=pressure, n=no of moles
Therefore,the gas having highest no of moles will have height partial pressure.
hence helium will have highest partial pressure.

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Similar questions

Q. A gaseous mixture contains

4.0

gm of

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and

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gm of

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Q. Gases

H_{2} H e O_{2} N_{2}

Critical temperature(K) 33.2 5.3 154.3 126

From the above data what whould be the order of liquefaction of these gases?
Start writing the order from the gas liquefying first.

Q. 12 g

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Q. A cylinder contains 0.3 mole

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Gases posses charcteristic critical temperature which depends upo the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.

$\begin{matrix} G a s e s & H_{2} & H e & O_{2} & N_{2} C r i t i c a l t e m p e r a t u r e i n K e l v i n & 33.2 & 5.3 & 154.3 & 126 \end{matrix}$

From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first

(a) $H_{2}, H e, O_{2}, N_{2}$ (b) $H e, O_{2}, H_{2}, N_{2}$

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A gaseous mixture contain 1 gm of H2, 4 gm of He 7gm of N2 and 8gm of O2. The gas having the highest partial pressure is:

A gaseous mixture contain 1 gm of $H_{2},$ 4 gm of $H e$ 7gm of $N_{2}$ and 8gm of $O_{2}$ . The gas having the highest partial pressure is: