Question

12 g of Mg (at. mass 24) will react completely with acid to give

• A. One mole of $H_2$
• B. $\frac{1}{2}$ mole of $H_2$
• C. $\frac{2}{3}$ mole of $O_2$
• D. Both $\frac{1}{2}$ mol of $H_2$ and $\frac{1}{2}$ mol of $O_2$

Answer 1

The correct option is B $\frac{1}{2}$ mole of $H_2$

$M{g}^{+2}\equiv H_2$
$n=\frac{12gm}{24gm}=\frac{1}{2}moleof{H}_2$