123 The molar solubility of CaF2 (Ks5.3 x10-11) in 0.1 M solution of NaF will be-Co5.3 x 10-11 mol L-1(2) 5.3 × 10-8 mol L-1A)-E) S.3 × 10-9 mol L-1くが(141) 5.3 × 10-10 mol L-1"卡

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10^{- 10} m o l^{2} L^{- 2}

10^{- 1} N

25^{\circ} C

L^{- 1}

If the solubility of calcium sulphate in water is $1.03 \times 10^{- 5}$ , what will be its solubility in $0.005 M$ solution of sulphuric acid?

A g C l

0.1 M N a C l

25^{o} C

2.0 \times 10^{- 10} m o l^{2} L^{- 2}

P b S O_{4}

M

N a_{2} S O_{4}

(K_{s p}

P b S O_{4} = 1.6 \times 10^{- 8})

L^{- 1}

A g C l

K_{s p} = 1.0 \times 10^{- 10}

0.1

K C l

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