124 is th term of the sequence 4, 9, 14, 19,.....

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Solution

The correct option is C 25
The given sequence is 4, 9, 14, 19... with the first term 4 and common difference d=5.
Let 124 be the nth term of the given sequence.
$a_{n} = 124 \Rightarrow a + (n - 1) d = 124 \Rightarrow 4 + (n - 1) 5 = 124 \Rightarrow (n - 1) \times 5 = 120 \Rightarrow (n - 1) = 24 o r, n = 25$

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