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Permutation: n Different Things Taken All at a Time When All Are Not Different.

129 : 145 : :...

Question

$129 : 145 :: 3811 : ?$

3713

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328

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346

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3615

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Solution

The correct option is D $3615$
In the first group 129 : 145
In 2nd number $1 + 4 = 5$ . So, last digit is sum of first two digits.
Now 1st two digits of 2nd number is obtained by adding 2 to the first two digits of first number.
And 3rd digit is obtained by subtracting 4 from the last digit of first number.
In 2nd group the order is reversed, since $3 + 8 = 11$ .
So, to obtain 2nd number we subtract 2 from the first two digits of $3811$ to get first two digits of 2nd number. And then we add 4 to the last two digits of $3811$ to get the last two digits of 2nd number.
Thus, we get the number $3615$ .
Hence, option 'D' is correct.

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129 - (129 - (130 - 30))

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