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Question

13.7+17.11+111.5+...+1(4n-1)(4n+3)=n3(4n+3)

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Solution

Let P(n) be the given statement.
Now,
P(n) =13.7+17.11+111.15+...+1(4n-1)(4n+3)=n3(4n+3)Step 1:P(1) =13.7=121=13(4+3)Hence, P(1) is true.Step 2:Let P(m) is true. Then,13.7+17.11+...+1(4m-1)(4m+3)=m3(4m+3)To prove: P(m+1) is true.That is,13.7+17.11+...+1(4m+3)(4m+7)=m+13(4m+7)Now,P(m) =13.7+17.11+...+1(4m-1)(4m+3)=m3(4m+3)13.7+17.11+...+1(4m-1)(4m+3)+1(4m+3)(4m+7)=m3(4m+3)+1(4m+3)(4m+7) Adding 1(4m+3)(4m+7) to both sides13.7+17.11+...+1(4m+3)(4m+7)=4m2+7m+33(4m+3)(4m+7)=(4m+3)(m+1)3(4m+3)(4m+7)=m+13(4m+7)Thus, P(m+1) is true.By the principle of mathematical induction, P(n) is true for all nN.

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