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Collision Theory

13. If activa...

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13. If activation energy of a backward reaction is -20 kJ/mol and that of forward reaction is 40kJ/mol, then enthalpy change for the reaction is 1. 20kJ/mol 2. 60kJ/mol 3. -20kJ/mol 4. -60kJ/mol Kindly explain with graph

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Q. The activation energy for the forward reaction

X \to Y

60 K J

{m o l}^{- 1}

Δ H

- 20 K J

{m o l}^{- 1}

. The activation energy for the backward reaction

Y \to X

Q. The activation energy for the forward reaction

X

\to

Y

60 k J

m o l^{- 1}

Δ H

- 20 k J

m o l^{- 1}

. The activation energy for the reverse reaction is:

Q. For a given reaction, energy of activation for forward reaction

(E_{a f})

80 k J / m o l

Δ H = - 40 k J / m o l

for the reaction. A catalyst lowers

E_{a f}

20 k J / m o l

. The ratio of energy of activation for reverse reaction before and after addition of catalyst is:

Q. The forward and backward activation energy of exothermic reaction

A \to B

80 and 280 k J m o l^{- 1}

respectively. The enthalpy change of the forward reaction

A \to B

k J / m o l

Q. In a reversible reaction, the enthalpy change and the activation energy in the forward direction are respectively

- x k J m o l^{- 1}

y k J m o l^{- 1}

. Therefore, the energy of activation in the backward direction, in

k J m o l^{- 1}

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