The activation energy for the forward reaction X- Y is 60KJ mol-1 and - H is -20KJ mol-1- The activation energy for the backward reaction Y- X is-

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Standard XII

Chemistry

Activation Energy

The activatio...

Question

The activation energy for the forward reaction $X \to Y$ is $60 K J$ ${m o l}^{- 1}$ and $Δ H$ is $- 20 K J$ ${m o l}^{- 1}$ . The activation energy for the backward reaction $Y \to X$ is:

80 K J

{m o l}^{- 1}

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40 K J

{m o l}^{- 1}

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60 K J

{m o l}^{- 1}

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20 K J

{m o l}^{- 1}

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Solution

The correct option is D $80 K J$ ${m o l}^{- 1}$
$⟹ Δ H = E_{a} (f) - E_{a} (b)$
$⟹ - 20 = 60 - E_{a} (b)$
$⟹ E_{a} (b) = 60 + 20$
$⟹ 80 K J m o l^{- 1}$

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The activation energy for the forward reaction X→Y is 60KJ mol−1 and ΔH is −20KJ mol−1. The activation energy for the backward reaction Y→X is:

The correct option is D 80KJ mol−1 ⟹ΔH=Ea(f)−Ea(b) ⟹−20=60−Ea(b) ⟹Ea(b)=60+20⟹80 KJmol−1

The activation energy for the forward reaction $X \to Y$ is $60 K J$ ${m o l}^{- 1}$ and $Δ H$ is $- 20 K J$ ${m o l}^{- 1}$ . The activation energy for the backward reaction $Y \to X$ is:

The correct option is D $80 K J$ ${m o l}^{- 1}$
$⟹ Δ H = E_{a} (f) - E_{a} (b)$
$⟹ - 20 = 60 - E_{a} (b)$
$⟹ E_{a} (b) = 60 + 20$
$⟹ 80 K J m o l^{- 1}$