137- If 1-tan- - k- then prove that - sec- - tan- - cosec- - is equal to -2-k-

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Trigonometric Ratio(sin,cos,tan)

137. If 1-tan...

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137. If 1-tanθ = k, then prove that ( secθ + tanθ + cosecθ ) is equal to [(2-k)

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Prove that : $\frac{t a n θ}{s e c θ - 1}$ - $\frac{t a n θ}{s e c θ + 1}$ = 2 cot $θ$

s e c θ - t a n θ = k,

s e c θ + t a n θ

t a n θ = m - \frac{1}{4 m}

s e c θ - t a n θ = - \frac{1}{k m}

x = s e c θ - t a n θ, y = c o s e c θ + c o t θ

x y + 1 =

\frac{1}{s e c θ - t a n θ} + \frac{1}{s e c θ + t a n θ} = 2 s e c θ

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