Question

14. 3(3x5) 2 9x 8 (r- 3)

Answer 1

Given, 37−( 3x+5 )≥9x−8( x−3 ).

Solve for x,

37−( 3x+5 )≥9x−8( x−3 ) 37−3x−5≥9x−8x+24 32−3x≥x+24 32−24≥x+3x

Further simplify,

8≥4x 2≥x

All the real numbers less than or equal to 2 are the solutions of inequality, as x is a real number.

Therefore, solution set is ( −∞,2 ].